How do you search for files containing dos line endings (CRLF) with grep on Linux?


Question

I want to search for files containing dos line endings with grep on Linux. Something like this:

grep -IUr --color '\r\n' .

The above seems to match for literal rn which is not what is desired.

The output of this will be piped through xargs into todos to convert crlf to lf like this

grep -IUrl --color '^M' . | xargs -ifile fromdos 'file'
1
113
12/9/2013 11:40:32 PM

Accepted Answer

Use Ctrl+V, Ctrl+M to enter a literal Carriage Return character into your grep string. So:

grep -IUr --color "^M"

will work - if the ^M there is a literal CR that you input as I suggested.

If you want the list of files, you want to add the -l option as well.

Explanation

  • -I ignore binary files
  • -U prevents grep to strip CR characters. By default it would do it if it decides it's a text file.
  • -r read all files under each directory recursively.
110
10/4/2017 8:50:12 AM

grep probably isn't the tool you want for this. It will print a line for every matching line in every file. Unless you want to, say, run todos 10 times on a 10 line file, grep isn't the best way to go about it. Using find to run file on every file in the tree then grepping through that for "CRLF" will get you one line of output for each file which has dos style line endings:

find . -not -type d -exec file "{}" ";" | grep CRLF

will get you something like:

./1/dos1.txt: ASCII text, with CRLF line terminators
./2/dos2.txt: ASCII text, with CRLF line terminators
./dos.txt: ASCII text, with CRLF line terminators

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