Can someone help explain the following:
If I type:
Then the output of the ls command is saved in the variable
but if I try:
The result is outputed to the shell (
stdout) rather than the variable
What I expected was the result operation of the shell trying to execute a scrip '
somefile' to be stored in the variable.
Please point out what is wrong with my understanding and a possible way to do this.
Just to clarify, the script '
somefile' may or may not exist. If it exsists then I want the output of the script to be stored in '
a'. If not, I want the error message "no such file or dir" stored in '
I think because the shell probably attaches itself to /dev/tty but I may be wrong. Why wouldn't you just set execute permissions on the script and use:
If you want to capture stderr and stdout to a, just use:
To check file is executable first:
if [[ -x ./somefile ]] ; then a=$(./somefile 2>&1) else a="Couldn't find the darned thing." fi
and you'll notice I'm switching to the $() method instead of backticks. I prefer $() since you can nest them (e.g., "
a=$(expr 1 + $(expr 2 + 3))").
You can try the new and improved way of doing command substitution, use $() instead of backticks.
If it still doesn't work, check if somefile is not actually stderr'ing.