How would you parse a date in bash, with separate fields (years, months, days, hours, minutes, seconds) into different variables?
The date format is:
Does it have to be bash? You can use the GNU coreutils
/bin/date binary for many transformations:
$ date --date="2009-01-02 03:04:05" "+%d %B of %Y at %H:%M and %S seconds" 02 January of 2009 at 03:04 and 05 seconds
This parses the given date and displays it in the chosen format. You can adapt that at will to your needs.