I was hoping:
cp -R src/prog.js images/icon.jpg /tmp/package
would yield a symmetrical structure in the destination dir:
/tmp | +-- package | +-- src | | | +-- prog.js | +-- images | +-- icon.jpg
but instead, both of the files are copied into /tmp/package. A flat copy. (This is on OSX).
Is there a simple bash function I can use to copy all files, including files specified by wildcard (e.g. src/*.js) into their rightful place within the destination directory. A bit like "for each file, run
mkdir -p $(dirname "$file"); cp "$file" $(dirname "$file")", but perhaps a single command.
This is a relevant thread, which suggests it's not possible. The author's solution isn't so useful to me though, because I would like to simply provide a list of files, wildcard or not, and have all of them copied to the destination dir. IIRC MS-DOS xcopy does this, but there seems to be no equivalent for cp.
Have you tried using the --parents option? I don't know if OS X supports that, but that works on Linux.
cp --parents src/prog.js images/icon.jpg /tmp/package
If that doesn't work on OS X, try
rsync -R src/prog.js images/icon.jpg /tmp/package
as aif suggested.
tar cf - <files> | (cd /dest; tar xf -)