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matching a line with a literal asterisk "*" in grep

bash grep regex

Question

Tried

$ echo "$STRING" | egrep "(\*)"

and also

$ echo "$STRING" | egrep '(\*)'

and countless other variations. I just want to match a line that contains a literal asterisk anywhere in the line.

1
21
10/23/2009 1:48:12 PM

Accepted Answer

Try a character class instead 

echo "$STRING" | egrep '[*]'
17
10/17/2009 3:18:00 AM

echo "$STRING" | fgrep '*'

fgrep is used to match the special characters.

Rohit_Sharma

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