In Bash, how do I count the number of non-blank lines of code in a project?
cat foo.c | sed '/^\s*$/d' | wc -l
And if you consider comments blank lines:
cat foo.pl | sed '/^\s*#/d;/^\s*$/d' | wc -l
Although, that's language dependent.
#!/bin/bash find . -path './pma' -prune -o -path './blog' -prune -o -path './punbb' -prune -o -path './js/3rdparty' -prune -o -print | egrep '\.php|\.as|\.sql|\.css|\.js' | grep -v '\.svn' | xargs cat | sed '/^\s*$/d' | wc -l
The above will give you the total count of lines of code (blank lines removed) for a project (current folder and all subfolders recursively).
In the above "./blog" "./punbb" "./js/3rdparty" and "./pma" are folders I blacklist as I didn't write the code in them. Also .php, .as, .sql, .css, .js are the extensions of the files being looked at. Any files with a different extension are ignored.